Questions
I want to autodetect system architecture, when i compile my program under freebsd and i want 2 includes for x64 and x32 but don t work, i tried like this :
ifeq ($(uname -a),i386)
INCDIR += -I../../x32
else
INCDIR += -I../../x64
endif
What is wrong here?
When i compile on amd64 work with code below.
When i compile on i388 don t work.
When i compile on amd64 with code below the makefile see x64 dir.
When i compile on i386 with code below the makefile see x64 dir.
Soo bassicaly that else don t have any effect ?
Answers
In GNU make syntax $() dereferences a variable. You rather want a shell command:
uname_p := $(shell uname -p) # store the output of the command in a variable
And then:
ifeq ($(uname_p),i386)
https://www.gnu.org/software/make/manual/make.html#Computed-Names
https://www.gnu.org/software/make/manual/make.html#Computed-Names
uname_s := $(shell uname -s)
$(info uname_s=$(uname_s))
uname_m := $(shell uname -m)
$(info uname_m=$(uname_m))
# system specific variables, add more here
INCDIR.Linux.x86_64 := -I../../x64
INCDIR.Linux.i386 := -I../../x32
INCDIR += $(INCDIR.$(uname_s).$(uname_m))
$(info INCDIR=$(INCDIR))
Which produces the following output:
$ make
uname_s=Linux
uname_m=x86_64
INCDIR=-I../../x64
Source
License : cc by-sa 3.0
http://stackoverflow.com/questions/36628165/gnu-makefile-detect-architecture
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