In JavaScript, I have an arbitrary number as input.
For example:
var number = parseFloat(12345678901234.1234567);
Now I want to display it as:
12 345 678 901 234.12
it should be
xxx xxx xxx.00
if it is an integer, and
xxx xxx xxx.y0
if only one digit after the decimal point
I would have assumed that this would do the trick:
var number = parseFloat(12345678901234.1234567);
console.log(number.toLocaleString( de-CH , { minimumFractionDigits:2, maximumFractionDigits: 2
}));
But it actually displayed 12 345 678 901 234.10 instead of 12 345 678 901 234.12
So I thought maybe I need to set minimumSignificantDigits to 2, too.
But bad luck, I discovered minimumSignificantDigits apparently considers all the digits in the string, for whatever idiotic reason, so I need to add the number of digits of the integer part to 2. Like:
var number = parseFloat(12345678901234.1234567);
console.log(number.toLocaleString( de-CH , { minimumFractionDigits:2, maximumFractionDigits: 2
,minimumSignificantDigits: parseInt(number).toString().length + 2
}));
But this still displays
12 345 678 901 234.10
Converting the float to the Number type doesn t help either, the output is still the same.
var number = Number(parseFloat(12345678901234.1234567));
console.log(number.toLocaleString( de-CH , { minimumFractionDigits:2, maximumFractionDigits: 2
,minimumSignificantDigits: parseInt(number).toString().length + 2
}));
I also tried this
var number = parseFloat(12345678901234.1234567);
number.toLocaleString( de-CH , {style: currency , currency: CHF , currencyDisplay: code }).replace( CHF , )
but it does not seem to work either.
Adding style: "decimal" doesn t help, either...
Additionally, I don t want to have to know the currency name for each locale.
What am I doing wrong ?
Is there really no other way than writing my own formatting code (where I have the problem that I don t know the thousand separator char for each locale) ?
Or is this a JavaScript bug for certain ?
