This is what I need and what I got. Add the numbers 3 through 10 to the hashtable Prompt the user for a string, and display the corresponding number. Using a loop and a single println statement, display all of the values (both strings and integers) in a table. My main problem is I m not sure what to do with the while loop. I have only worked with a while loop once.
import java.util.*; class HTDemo { public static void main(String args[]) { Hashtable<String, Integer> numbers = new Hashtable<String, Integer>(); numbers.put("one", new Integer(1)); numbers.put("two", new Integer(2)); numbers.put("three", new Integer(3)); numbers.put("four", new Integer(4)); numbers.put("five", new Integer(5)); numbers.put("six", new Integer(6)); numbers.put("seven", new Integer(7)); numbers.put("eight", new Integer(8)); numbers.put("nine", new Integer(9)); numbers.put("ten", new Integer(10)); String number; Scanner input = new Scanner(System.in); System.out.println("Enter a number in word form: (Example: Five, Six, Seven): "); number = input.next(); while () { System.out.println("You entered: " + number + " which is the interger: " + numbers); } } }
This is what I get, it s not right to the instructions:
Enter a number in word form: (Example: Five, Six, Seven):
five
You entered: five
which is the integer: {three=3, six=6, ten=10, seven=7, nine=9, one=1, five=5, four=4, two=2, eight=8}